y=3y^2+5y+6

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Solution for y=3y^2+5y+6 equation: 



y=3y^2+5y+6

We move all terms to the left:

y-(3y^2+5y+6)=0

We get rid of parentheses

-3y^2+y-5y-6=0

We add all the numbers together, and all the variables

-3y^2-4y-6=0

a = -3; b = -4; c = -6;
Δ = b2-4ac
Δ = -42-4·(-3)·(-6)
Δ = -56
Delta is less than zero, so there is no solution for the equation

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